Author | Topic: super classes and interfaces |
priyavardheesh greenhorn |
posted May 01, 2000 02:28 PM
hi everybody, abstract class Super interface Design class Sub extends Super implements Design getting
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edward man unregistered |
posted May 01, 2000 06:56 PM
Here is my version:
It doesn't matter what shape() it is as long as both of them having the same signature in Super and Design. When you implement the shape () method in a subclass you are actually overriding the one in both Super and Design. One thing to watch is all methods declared in an interface are implicitly declare public. That's why I have to declare "public void shape ()" in the subclass. Without the public modifier, the java compiler will complain.
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Tony Alicea sheriff |
posted May 01, 2000 07:16 PM
That one I don't have time to test (I already passed Certification) but I'm sure you have the time if you're still studying From what I remember reading is that since both methods have the same signature, one implementation will satisfy both at the same time... Your mileage may vary...
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maha anna bartender |
posted May 01, 2000 07:57 PM
If the return type of the 2 methods with the same name would have been different, then the compiler is confused and yells at us. . Because it does not know which method, the subclass could possibly implement. You can't have 2 methods with same signature and different return types in the same class right? regds [This message has been edited by maha anna (edited May 01, 2000).]
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