| Author | Topic: Overriding Methods |
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J. Scott Smith greenhorn |
posted March 09, 2000 01:42 PM
If you had the following in the super class: public final amethod(){} And in a subclass of the super class you had the following method: public final amethod(){} Would you be able to use the same final method verbatim without causing a compiler error? (I am aware that a final method cannot be overriden in a subclass, but can it be used as is in an overloaded capacity? I also understand that this is a strange question and probably would not come up in reality, but I am trying to learn all possible loopholes for this modifier.) Also, what would happen if you tried to override a private method?
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maha anna bartender |
posted March 09, 2000 01:56 PM
Whenever you overload a method either in the same class or in one of its subclasses you CAN DO whatever you want with that new overloaded method. The overloaded method is a COMPLETELY NEW method which happened to have the same name as the other. Regarding private methods , they are known ONLY to the class within which it is defined.The subclasses DO NOT EVEN know that such a method exists in one of their superclasses. One more point is all private methods are implicitly final. Isn't it? But the vice versa is may/may not be true. (i.e) a final method may be declared as private/protected/public. [This message has been edited by maha anna (edited March 09, 2000).]
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J. Scott Smith greenhorn |
posted March 09, 2000 02:28 PM
Thank you Maha Anna.
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