class Sub
{
public static void main(String ards[])
{
int x = 0;
boolean b1, b2, b3, b4;
b1 = b2 = b3 = b4 = true;

x = ( b1 | b2 & b3 ^ b4) ? x++ : --x;
System.out.print(x);
}
}

The expression can be solved in the following manner:
Using the following operator preceence:
1> & AND
2> ^ XOR
3> | OR

x = (true | ( true & true ) ^ true) ----- 1
x = (true | (true ^ true ) ) -------------2
x = (true | false) -----------------------3
x = true

x evaluates to true so the answer is 0.

The expression x = (b1|b2&b3^b4) ? x++ : --x; means

if(b1|b2&b3^b4)
x = x++;
else
x = --x;
System.out.print(x)

Now the boolean codn (b1|b2&b3^b4) returns true. So x = x++ should execute. My question is then x should be 1 instead of zero(because of x++)in the o/p. I just don't know why it is showing zero !

shatabdi