int iBegin=1;

char iEnd=3; //seeThis is char and Not int

System.out.println(s.substring(iBegin,iEnd));

1) Bic
2) ic
3) icy
4) error: no method matching substring(int,char)
Ans:2

Well the answer is right and the extract from JLS is produced below for reference.

20.12.32 public String substring(int beginIndex, int endIndex)
throws IndexOutOfBoundsException

The result is a newly created String object that represents a subsequence of the character sequence represented by this String object; this subsequence begins with the character at position beginIndex and ends with the character at position endIndex-1 . Thus, the length of the subsequence is endIndex-beginIndex.

If beginIndex is negative, or endIndex is larger than the length of this String object, or beginIndex is larger than endIndex, then this method throws an IndexOutOfBoundsException.

Examples:

"hamburger".substring(4, 8) returns "urge"
"smiles".substring(1, 5) returns "mile"

Hope this helps

Thanks
Ajay

Here char range is from 0 to (2^16)-1. So value 10 is within this range. So this is valid statement.
At the same time this is NOT valid.

byte b = 1000; // Not valid
byte b1 = 100; //Valid
byte b2 = 127; //valid

Also note that this rule is NOT APPLICABLE for method invocation.
For example there is a method like the foll

void m1(byte b, char c, short s) { }

The you CAN NOT call the above method like this

m1(10,20,30); // NOT VALID

Here the 'int' literals are treated as 'int' type and you have to specifically cast them to byte/char/short.

m1((byte)10,(char)20,(short)30); // VALID

regds
maha anna

class TestProgram
{
public static void main(String[] args)
{
byte a = 100;
char c = 67;
testMethod(a, c);
}
static void testMethod(byte b, char d)
{
System.out.println("byte = " + b + " char = " + d);
}
}

The output is:
byte = 100 char = C