What is the result of executing the following code

class Test {
public static void main(String[] args) {
Test t = new Test();
t.test(1.0, 2L, 3);

}
void test(double a, double b, short c) {

System.out.println("1");
}
void test(float a, byte b, byte c) {

System.out.println("2");
}
void test(double a, double b, double c) {

System.out.println("3");
}
void test(int a, long b, int c) {

System.out.println("4");
}
void test(long a, long b, long c) {

System.out.println("5");
}
}
a)1
b)2
c)3
d)4
e)5

His answer is c.
Why it cant be a?? Also I dont understand his explanation in the answer which says.

" The method with all double parameters is actually the only version of test() that the Java Virtual Machine can legally coerce the numbers to. The reason the other versions of test() are not invoked is that at least one of the parameters would have to be automatically coerced from a type with greater accuracy to a type with less accuracy, which is illegal. "

Can anybody help me??

These "automatic" conversions are called widening conversions they are always OK and don't need a cast since no information is going to be lost by the conversion. The opposite, narrowing conversions, (as in (a), attempting to convert an int into a short) require explicit casting because of the possibility of lost information/accuracy.

byte b = 12;

Isn't 12 an int? Why is it not necessary to do

byte b = (byte) 12;

 
     void test(double a, double b, short c) { 
        System.out.println("1");
     } 
     t.test(1.0, 2L, 3);